名校
解题方法
1 . 在世界环保意识日益强化,石油资源日渐沽竭的今天,以氢气做动力源的研究已成为一大课题.当年马自达坚持下来的转子发动机(如图1)从结构上讲是最适合燃烧氢气,而且最“干净”,因为氢燃烧完后排出的是水蒸气,对环境没有任何污染.马自达公司改制了RX-7型跑车的转子发动机,使它可以用氢做燃料.以正四面体的四个顶点为球心,以正四面体的棱长为半径的四个球的相交部分围成的几何体(如图2)被称为“勒洛四面体”,它表面上任意两点间的距离最大值与正四面体棱长相等,能在两个平行平面间自由转动,并且始终保持与两平面都接触,因此它能像球一样来回滚动.转子发动机的设计正是利用了这一原理.转子引擎只需转一周,各转子便有一次进气、压缩、点火与排气过程,相当于往复式引擎运转两周,因此具有小排气量就能成就高动力输出的优点.另外,由于转子引擎的轴向运动特性,它不需要精密的曲轴平衡就可以达到非常高的运转转速.若正四面体ABCD的棱长为2,将对应的勒洛四面体ABCD放进一个正方体纸盒中,若该勒洛四面体可以在纸盒内任意转动,则该纸盒棱长的最小值为__________ ;若在勒洛四面体ABCD内放一个小正方体零件,该零件可以在勒洛四面体ABCD内任意转动,则该零件棱长的最大值为__________ .
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7日内更新
|
29次组卷
|
2卷引用:云南省曲靖市民族中学2022-2023学年高二上学期教学测评开学考试数学试卷
名校
解题方法
2 . 已知正三棱锥
的顶点为
,底面是正三角形
.
两两所成角为
,设质点
自
出发,依次沿着三个侧面移动环绕一周,直至回到出发点
,求质点移动路程的最小值;
(2)若该三棱锥的所有棱长均为1,求以
为顶点,以三角形
内切圆为底面的圆锥的侧面积;
(3)若该三棱锥的体积为定值
,求该三棱锥侧面与底面所成的角
的正切值,使该三棱锥的表面积
最小.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63397cda22cb1fad59cf966dfb588643.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bef5239ddbb0972700ce01daf9ee7cf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/19bb1063e139610045f3bca5ca0b2766.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fea31f8a526b3d83b099f43086ba950d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/91edc7e2d4811f5ea6c01284cf00393a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
(2)若该三棱锥的所有棱长均为1,求以
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bef5239ddbb0972700ce01daf9ee7cf.png)
(3)若该三棱锥的体积为定值
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be54e84508decfcce6d2fcbe6c8c1a92.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf231f8f86fb922df4ca0c87f044cec3.png)
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3 . 求满足下列条件的曲线方程:
(1)已知双曲线的焦点在x轴上,离心率为
,且经过点
;
(2)若动点P在
上移动,求点P与点
连线的中点的轨迹方程.
(1)已知双曲线的焦点在x轴上,离心率为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/caa585b9257ed0798213a9ae9b87d291.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8c9524efddc807d6c9ebf37b1cf37628.png)
(2)若动点P在
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2751c5819303b8e60add2356bd7c808b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/203b64e2a9e4ac8bdfb1b541597f7119.png)
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解题方法
4 . 已知.
(1)若角
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/901d78ddfff74884866bc5067476a676.png)
(2)若将角
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15615de1a6df206dbd081251f676578e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6581916f5a65edfea257c804efee007e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a5ec0ffb548604f2055fa27127266349.png)
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5 . 数学家祖冲之曾给出圆周率
的两个近似值:“约率”
与“密率”
它们可用“调日法”得到:称小于
的近似值为弱率,大于
的近似值为强率
由
,取
为弱率,
为强率,得
,故
为强率,与上一次的弱率
计算得
,故
为强率,继续计算,
若某次得到的近似值为强率,与上一次的弱率继续计算得到新的近似值;若某次得到的近似值为弱率,与上一次的强率继续计算得到新的近似值,依此类推
______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/70f5389990c3a0c5373f3bd9fb2454c9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/598564aec706dff769c5afc4c378c572.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8fe06931e9309ab626a087f252cf4c46.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ba8b2ddd6646a556f0a0e0ab5b15c9cc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fb9b8fd11f9a3d287e956df276667615.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c90282d4a37c9a20620d4bbb0c263cae.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/160ae6f860b2c27244b64dc511890a4b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ca7d1107389675d32b56ec097464c14.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b8860d9787671b53b1ab68b3d526f5ca.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/167765a997bbc662e4ea8f0183848897.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e72adb45c60c2f63b46e65ff787302bf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ca7d1107389675d32b56ec097464c14.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bb92d6017d8d5cdb1d5cceecfcb3689b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3e88093a749c0d46e0ee931ecfaff925.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a299a08c7f87220f9eca82a1f7a055b4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0382b4a2ab0657d2d6830bb6be2b17b6.png)
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6 . 如图,若长方体
的底面是边长为2的正方形,高为
是
的中点,则正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/917b057d142e0b8421a9cf83ddec7095.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/22adbc0da438220f9cace11b629d799b.png)
A.![]() | B.平面![]() ![]() |
C.三棱锥![]() ![]() | D.三棱锥![]() ![]() |
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2024-03-21更新
|
439次组卷
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6卷引用:云南省大理白族自治州民族中学2023-2024学年高二下学期见面考试数学试题
解题方法
7 . 已知某圆锥的底面圆半径为1,且该圆锥侧面展开图的圆心角为
,则该圆锥的外接球的体积为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7cd206f0986ffb465d929394f0192f51.png)
A.![]() | B.![]() | C.![]() | D.2![]() |
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8 . 已知函数
的定义域为R,其图象关于点
对称.
(1)求实数a,b的值;
(2)求
的值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/577e63848aec77f9b940f0f2fb86ccee.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e497e1c174c15d2053ec062978272066.png)
(1)求实数a,b的值;
(2)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1db62cd86e68df8489b620a058d13bf9.png)
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解题方法
9 . 给定椭圆
:
,我们称椭圆
为椭圆
的“伴随椭圆”.已知
,
分别是椭圆
的左、右顶点,
为椭圆
的上顶点,等腰
的面积为
,且顶角的余弦值为![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f30d314a642667fef559032264647366.png)
(1)椭圆
的方程;
(2)
是椭圆
上一点(非顶点),直线
与椭圆
的“伴随椭圆”交于
,
两点,直线
与椭圆
的“伴随椭圆”交于
,
两点,证明:
为定值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/58a0b452fd57bbdc105589e871baa009.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f2d73d3c62b31d1539ae298a1756ed6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/95bacae35b6e16a0a33c2bdc6bc07df7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f30d314a642667fef559032264647366.png)
(1)椭圆
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
(2)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/20a541b81584a032f571159ea152c85a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/895dc3dc3a6606ff487a4c4863e18509.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/73465a1f9aa03481295bf6bd3c6903ac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2cdba1337ec85fa9722cb4b320a82ae6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8886aafdad72d6153ef337d8793c9865.png)
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10 . 如图,为了测量某塔的高度,无人机在与塔底B位于同一水平面的C点测得塔顶A的仰角为45°,无人机沿着仰角α(
)的方向靠近塔,飞行了
m后到达D点,在D点测得塔顶A的仰角为26°,塔底B的俯角为45°,且A,B,C,D四点在同一平面上,求该塔的高度.(参考数据:取 tan 26°=
,cos 56°=
)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ab1c17a53981687048cb4906307f8b0b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8f2eae4bfb82c3ab183c4d47b4ea12a7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b696b79a748797ef1e56fa31ee9a450d.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/3/13/510ecde0-f63f-4f01-bf7d-2713f863f92f.png?resizew=142)
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