名校
解题方法
1 . 关于
的不等式
有解,则实数
的取值范围是___________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b021b127a6d00ae353a46bf995427923.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
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2 . 已知
,
,对任意的
都有
,则
的取值范围是_______
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e2c78fc54dee0dee8c889114611906df.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83655a9220769796fe153f023528c91f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0c0aa2ef928b6e3341d0a0dc6d8055b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6ae828be829213bd6b66651dce99263c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
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名校
3 . 用数学的眼光看世界就能发现很多数学之“美”.现代建筑讲究线条感,曲线之美让人称奇,衡量曲线弯曲程度的重要指标是曲率,曲线的曲率定义如下:若
是
的导函数,
是
的导函数,则曲线
在点
处的曲率
.
在
处的曲率
的平方;
(2)求余弦曲线
曲率
的最大值;
(3)余弦曲线
,若
,判断
在区间
上零点的个数,并写出证明过程.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/090a91e4f3c8930674f98a9fa527709b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d275fbb3ee5cd1177ca5a2ceecbbef0f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0bac50c92211d6348b056335f6c83ea1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/090a91e4f3c8930674f98a9fa527709b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0afb80007983e5b99dcdeebf87d18ff4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e669b77945df783df093b549ac2a67d7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83bdb811e83e6f94b20dfa3ab68b1096.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/391039b1ebf01aa7def8a44c97ea05b7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9311b13eb2baab6641da9e7b48e13e24.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e029cc1f7d07eeb136bd3946a7eb23e3.png)
(2)求余弦曲线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/832d87f3c6bd439ef3d84a6c6da3642e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/32410867843f1a7ef11410da8f3f8dab.png)
(3)余弦曲线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/832d87f3c6bd439ef3d84a6c6da3642e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2cbffb683ddd3767c5ebd35ac9212f6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/028517e8bebe634441e0a5c79828e88a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/877e6c30566e9d9b11ecf5b78f4c5e73.png)
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4 . 已知双曲线
的焦距为
,点
在C上.
(1)求C的方程;
(2)直线
与C的右支交于
两点,点
与点
关于
轴对称,
点在
轴上的投影为
.
①求
的取值范围;
②求证:直线
过点
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83bf4fd84818abac17a9d21237ac5ce5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b91d650c2fc1a741fabdb333b09aeb6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dd0c551cfc411bdb73d2d94e72a274ce.png)
(1)求C的方程;
(2)直线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7dd3612e4030088fb56b6d51c8e44c43.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7ae1567d8f98fabc1a3948f8602cc5e7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/895dc3dc3a6606ff487a4c4863e18509.png)
①求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/478594ad23987a11ca48c0ff31b329bb.png)
②求证:直线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d0213c5787a5a6b38d11bceca5567f67.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/895dc3dc3a6606ff487a4c4863e18509.png)
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解题方法
5 . “费马点”是由十七世纪法国数学家费马提出并征解的一个问题,该问题是:“在一个三角形内求作一点,使其与此三角形的三个顶点的距离之和最小”.如图1,三个内角都小于
的
内部有一点
,连接
,求
的最小值.我们称三角形内到三角形三个顶点距离之和最小的点为费马点.要解决这个问题,首先应想办法将这三条端点重合于一点的线段分离,然后再将它们连接成一条折线,并让折线的两个端点为定点,这样依据“两点之间,线段最短”,就可求出这三条线段和的最小值.某数学研究小组先后尝试了翻折、旋转、平移的方法,发现通过旋转可以解决这个问题,具体的做法如图2,将
绕点
顺时针旋转
,得到
,连接
,则
的长即为所求,此时与三个顶点连线恰好三等分费马点
的周角.同时小组成员研究教材发现:已知对任意平面向量
,把
绕其起点沿逆时针方向旋转
角得到向量
.
,把点
绕点
沿顺时针方向旋转
后得到点
,求点
的坐标;
(2)在
中,
,借助研究成果,直接写出
的最小值;
(3)已知点
,求
的费马点
的坐标.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/231b861d6d1f1d0b9f52b041cb40eb62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/19bb1063e139610045f3bca5ca0b2766.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c7ed53a398b1d6b7b4abbb43a9abcf1f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9524e3810e06dc781285f1289e75d653.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2d5bca00fa20e6e80480b9d06d2e52ee.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f850c705372b8a85489505da53239fd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5643311f49a8c6f64b2a2788f79458e4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/85c4bdfb0db1e31e8459df1d15f9ab55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5f478a74bccc9b8d7745b08c5484f238.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/abcb5d89b04570ceda2c29e11cb27a57.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/89756ef947f1add6a68efa8998430dc4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7de03fc9682ff77d327a5681010ab3b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15615de1a6df206dbd081251f676578e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
(2)在
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b11bf8ee11289d13cf5dd0ea9505e699.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c7ed53a398b1d6b7b4abbb43a9abcf1f.png)
(3)已知点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/24a65f35281b21fdfaf7c437fbd321eb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
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名校
6 . 在同一平面直角坐标系中,
分别是函数
和函数
图象上的动点,若对任意
,则
最小值为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7789a500686c7a73770404ead6af0590.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8e9e0c6acf97351409b3fe2d30054a95.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c8faa5f6f296bd3c08757b697df7a7a6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/94440d3e4c073f94f2b266ff99d50e74.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/084cf5ffced059f5653ee2a1023518b7.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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昨日更新
|
111次组卷
|
2卷引用:四川省成都石室中学2024届高三下学期高考适应性考试(一)理科数学试题
解题方法
7 . 已知O为坐标原点,椭圆
左、右焦点分别为
,短轴长为
,过
的直线
与椭圆
交于
两点,
的周长为8.
(1)求
的方程;
(2)若直线l与Ω交于A,B两点,且
,求|AB|的最小值;
(3)已知点P是椭圆Ω上的动点,是否存在定圆O:x2+y2=r2(r>0),使得当过点P能作圆O的两条切线PM,PN时(其中M,N分别是两切线与C的另一交点),总满足|PM|=|PN|?若存在,求出圆O的半径r:若不存在,请说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a51be38237df3982ee2615a2e20830e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4d2a97987f71835f519b462f5b8f5957.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/38387ba1cadfd3dfc4dea4ca9f613cea.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f5076289823db419f94e9c0c8f4aafd9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cffa35373ec4e4684107b42adb7a5161.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/39acab3cfb59bfc9591371721ab01d93.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/24c084b48b27ce17a659fb3e9b79d684.png)
(1)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cffa35373ec4e4684107b42adb7a5161.png)
(2)若直线l与Ω交于A,B两点,且
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cc11e7549cfce9220e70250ac943e457.png)
(3)已知点P是椭圆Ω上的动点,是否存在定圆O:x2+y2=r2(r>0),使得当过点P能作圆O的两条切线PM,PN时(其中M,N分别是两切线与C的另一交点),总满足|PM|=|PN|?若存在,求出圆O的半径r:若不存在,请说明理由.
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解题方法
8 . 已知
,
,是双曲线C:
的左右焦点,过
的直线与双曲线左支交于点A,与右支交于点B,
与
内切圆的圆心分别为
,
,半径分别为
,
,若
,则双曲线离心率为________ .
的取值范围为________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f5076289823db419f94e9c0c8f4aafd9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3fb78c5f885034612c0e030b920143d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/19f3fa0b40fb0d9b8c62e37316ab3b04.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f5076289823db419f94e9c0c8f4aafd9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b2cfd997d3b66a3b8f7731b26f0ab0c8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/47444b5fbc4252516d54263062e47c81.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2f1ac49b4139636fb1809fe970b23a87.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2d1a0fd1ad044a9ecfcba672779bd678.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2858005b9ae89ae080d83dcc13cf8e81.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2b3e95410f3b4fcb0cba425b521d1f67.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fcccefb64de9d739bb52695c8cf38fe9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eeaf446f8478f36f56884039d517104c.png)
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9 . 已知函数
,
的定义域为
.
(1)求
的极值点;
(2)讨论
的单调性;
(3)若函数
存在唯一极小值点,求
的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/270679f83d2f89307b9b7080cf81203a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5d9ee1df512f2ebc9e6cff9953b805b8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d562dc22dfb3b81d0c3f88b54d063c2f.png)
(1)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4669810732b633b60dbeaf0bf57204f6.png)
(2)讨论
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09f86f37ec8e15846bd731ab4fcdbacd.png)
(3)若函数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2df17d1b404651bf6dbc97b519d452e1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
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解题方法
10 . 降维类比和升维类比主要应用于立体几何的学习,将空间三维问题降为平面二维或者直线一维问题就是降维类比.平面几何中多边形的外接圆,即找到一点,使得它到多边形各个顶点的距离相等.这个点就是外接圆的圆心,距离就是外接圆的半径.若这样的点存在,则这个多边形有外接圆,若这样的点不存在,则这个多边形没有外接圆.事实上我们知道,三角形一定有外接圆,如果只求外接圆的半径,我们可通过正弦定理来求,我们也可以关注九年义教初中《几何》第三册第94页例2.的结论:三角形外接圆的直径等于两边的乘积除以第三边上的高所得的商.借助求三角形外接圆的方法解决问题:若等腰梯形
的上下底边长分别为6和8,高为1,这个等腰梯形的外接圆半径为__________ ;轴截面是旋转体的重要载体,圆台的轴截面中包含了旋转体中的所有元素:高、母线长、底面圆的半径,通过研究其轴截面,可将空间问题转化为平面问题.观察图象,通过类比,我们可以找到一般圆台的外接球问题的研究方法,正棱台可以看作由圆台切割得到.研究问题:如图,正三棱台的高为1,上、下底面边长分别为
和
,其顶点都在同一球面上,则该球的体积为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/adbd3e8cf8325999cde03adf845d3dd0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/41322821ce31416fdac8dd6e0aa41c71.png)
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