1 . 用一个不垂直于圆锥的轴的平面截圆锥,当圆锥的轴与截面所成的角不同时,可以得到不同的截口曲线,也即圆锥曲线.探究发现:当圆锥轴截面的顶角为
时,若截面与轴所成的角为
,则截口曲线的离心率
.例如,当
时,
,由此知截口曲线是抛物线.如图,圆锥
中,
、
分别为
、
的中点,
、
为底面的两条直径,且
、
,
.现用平面
(不过圆锥顶点)截该圆锥,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f8dd0c52aca1675c17b9a019aa7901e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e44f6ec575a7e7efb670d5c39bdcc2e7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ffa3205b1df826d63914dcb55bb3ab43.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09dbcaa127022fbd6b6f13345196408a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/18e5ef91fb27dd684a27ae7f1993cfba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/defa5b53043ae802bb1af7d14374406d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/18e5ef91fb27dd684a27ae7f1993cfba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a77e3c1c236141d6118429fade0a9b9d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3d2c15801fee2405573677484f5dcfa4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1a727432fbf5b502786cdb18b84b8920.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9f435efcc7869eec21bdba1ed81dc3f5.png)
A.若![]() |
B.若![]() ![]() ![]() |
C.若![]() |
D.若截口曲线是离心率为![]() ![]() |
您最近一年使用:0次
2024-06-08更新
|
472次组卷
|
2卷引用:云南省昆明市第三中学2024届高三下学期高考考前检测数学试卷
解题方法
2 . 在矩形
中,
,
,以对角线BD为折痕将△ABD进行翻折,折后为
,连接
得到三棱锥
,在翻折过程中,下列说法正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ced06b71073e1bb777f326f06016ce17.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f656e1d1f68954e5f06de8958f6a9310.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3ea25ef38e4afa8f75ffd0842890289.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6eb97aff0960e2640314888a38e7169c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eeb4c6e9a723aa843e6ba62d7c1a3a6c.png)
A.三棱锥![]() ![]() | B.点![]() |
C.点![]() ![]() | D.当![]() ![]() |
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3 . 已知
为抛物线
上的三个点,且
,当点
与原点О重合时,
,则下列说法中,正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f6a68919c5cf3775eb79dfc3fcfc2e69.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3764ba3aa0a241787f4661026bb14053.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/860b76e47ec09b73eee198cc86b33b2a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/890c3adc2db9d97a4353a5abaccd6519.png)
A.抛物线方程为![]() |
B.直线AB的倾斜角必为锐角 |
C.若线段AC的中点纵坐标为![]() ![]() |
D.当AB的斜率为2时,B点的纵坐标为![]() |
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解题方法
4 . 牛顿迭代法是求函数零点近似值的一种方法,它的原理是利用曲线一系列切线与
轴交点的横坐标来逼近函数的零点.已知
,设
,
为
的两个零点(
<
),令
,在点
处作函数
的切线,设切线与
轴的交点为
,继续在点
处作函数
的切线,切线与
轴的交点为
,……如此重复,得到一系列切线,它们与
轴的交点的横坐标形成数列
,易得
(
),设
(
),
的前
项和为
,则下列说法中,正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ea8167d7170d35d1ec34c58274450cc3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4fe7d5809da02c15a43a0e9a898b9086.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bbe7bdaaf8b0adf10bf2ef6c1255b1dc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a34f9d53165bce1f4e5d430ca013c1c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4fe7d5809da02c15a43a0e9a898b9086.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3e88093a749c0d46e0ee931ecfaff925.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3a63287530c643a667f401dea61a9955.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4fe7d5809da02c15a43a0e9a898b9086.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6c1ccc6c74b8754e9bcbb3f39a11b6f1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76aef4cdcb5af742ce28003b7b6c8c20.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3b6a46c5fb744758ad83902819b83bbf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/209591cfb9f8271f5ad48d89f214f22e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ff3f09212ff19257fd0480603af58099.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15a70b95c53fb6655721e2a8c61f5c2c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f329b217e1051b23f0d61023cdc6e69.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f1ae9a3b0b7aeb1545b65d91aa371b3c.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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名校
解题方法
5 . 在
中,
为
的中点,点
在线段
上,且
,将
以直线
为轴顺时针转一周围成一个圆锥,
为底面圆上一点,满足
,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ad321498d5dbccc103e27859cfcad347.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/facc34ca1966664602c12de6152fa8e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/432d1735ec51fb10d3dfa0b8175fd126.png)
A.![]() |
B.![]() ![]() ![]() |
C.直线![]() ![]() ![]() |
D.直线![]() ![]() ![]() |
您最近一年使用:0次
2024-04-07更新
|
1049次组卷
|
4卷引用:云南省昆明市部分学校2024届高三下学期二模考试数学试题
名校
6 . 某批水稻种子有5%的是变异种,变异种当中有90%的是长不大的.在正常的种子中,90%的都能长大.下列说法正确的有( )
A.这批水稻长不大的占比超过10% |
B.这批水稻种子既是变异种又是长不大的概率低于1% |
C.如果有种子长不大,那么它是变异种的概率高于30% |
D.如果有种子长大了,那么它是变异种的概率高于0.3% |
您最近一年使用:0次
2024-03-29更新
|
593次组卷
|
4卷引用:云南省昆明市第三中学2023-2024学年高二下学期5月期中考试数学试题
云南省昆明市第三中学2023-2024学年高二下学期5月期中考试数学试题浙江省精诚联盟2023-2024学年高二下学期3月联考数学试题(已下线)专题3.1条件概率与全概率公式(四个重难点突破)-2023-2024学年高二数学下学期重难点突破及混淆易错规避(人教A版2019)(已下线)第七章:随机变量及其分布章末综合检测卷(新题型)-2023-2024学年高二数学题型分类归纳讲与练(人教A版2019选择性必修第三册)
名校
解题方法
7 . 如图,角
,
的始边与x轴的非负半轴重合,终边分别与单位圆交于A,B两点,M为线段AB的中点.N为
的中点,则下列说法中正确的是( )
![](https://img.xkw.com/dksih/QBM/editorImg/2024/3/8/dcbff410-1dc2-49b1-ae4d-b729755149e4.png?resizew=161)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/66270dff1414f945b80177516091a237.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/16d65cecaf8a3dc2953f4109c75a981e.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/3/8/dcbff410-1dc2-49b1-ae4d-b729755149e4.png?resizew=161)
A.N点的坐标为![]() |
B.![]() |
C.![]() |
D.若![]() ![]() |
您最近一年使用:0次
名校
8 . 已知函数
,则下列说法正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/74dfcce112fb8badf9ba95df6108c763.png)
A.若![]() ![]() ![]() |
B.若![]() ![]() ![]() |
C.若![]() ![]() |
D.当![]() ![]() ![]() ![]() |
您最近一年使用:0次
2024-03-25更新
|
1412次组卷
|
4卷引用:云南省昆明市第一中学2024届高三第七次高考仿真模拟数学试题
解题方法
9 . 设
,
为椭圆
:
的左右顶点,
,
为
的左、右焦点,点
在
上,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/44d12ebd10f6c0bcf98be52c32b107f1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f5076289823db419f94e9c0c8f4aafd9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3fb78c5f885034612c0e030b920143d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
A.当椭圆![]() ![]() ![]() |
B.在椭圆![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() |
C.若点![]() ![]() ![]() ![]() ![]() ![]() |
D.不存在点![]() ![]() |
您最近一年使用:0次
10 . 多项选择题给出的四个选项中,有多项是符合题目要求的,全部选对得5分,部分选对得2分,有选错的得0分.小乐同学在面对一道多项选择题时,仅能明确的排除一个错误选项A,于是她选择在B、C、D三个选项中随机填涂答案提交,若该题在B、C、D中只有两个选项正确,则( )
A.若小乐填涂三个选项,则该题得2分的概率为![]() |
B.若小乐随机填涂一个选项,则该题得0分的概率为![]() |
C.若小乐随机填涂两个选项,则该题得5分的概率为![]() |
D.若小乐随机填涂两个选项,则该题得0分的概率为![]() |
您最近一年使用:0次