名校
解题方法
1 . 某雕刻师在切割玉料时,切割出一块如图所示的三棱锥型边料,测得在此三棱锥
中,侧面
底面
,且
,该雕刻师计划将其打磨成一颗球形玉珠,则磨成的球形玉珠的直径的最大值为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/891579e7c231584a8e16b8eeff79888e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3d7090639341730951c1bc3c9b6164e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ca67a5b8f69507c8b80379e86f90a8ce.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fe3faa82da218bcd6aaf987a4743954c.png)
A.![]() | B.![]() |
C.![]() | D.![]() |
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2 . 某大型商场的所有饮料自动售卖机在一天中某种饮料的销售量
(单位:瓶)与天气温度
(单位:
)有很强的相关关系,为能及时给饮料自动售卖机添加该种饮料,该商场对天气温度
和饮料的销售量
进行了数据收集,得到下面的表格:
经分析,可以用
作为
关于
的经验回归方程.
(1)根据表中数据,求
关于
的经验回归方程(结果保留两位小数);
(2)若饮料自动售卖机在一天中不需添加饮料的记1分,需添加饮料的记2分,每台饮料自动售卖机在一天中需添加饮料的概率均为
,在商场的所有饮料自动售卖机中随机抽取3台,记总得分为随机变量
,求
的分布列与数学期望.
参考公式及数据:对于一组数据
,经验回归方程
的斜率和截距的最小二乘估计公式分别为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/de96374212b9a5df820d78d10e7d1291.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![]() | 10 | 15 | 20 | 25 | 30 | 35 | 40 |
![]() | 4 | 16 | 64 | 256 | 2048 | 4096 | 8192 |
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e8029f44c190cd8ced93ed27ba0c18b6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
(1)根据表中数据,求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
(2)若饮料自动售卖机在一天中不需添加饮料的记1分,需添加饮料的记2分,每台饮料自动售卖机在一天中需添加饮料的概率均为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4dac452fbb5ef6dd653e7fbbef639484.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f022950e0faa45b617d497b01b5292b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f022950e0faa45b617d497b01b5292b9.png)
参考公式及数据:对于一组数据
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eafbe64ec9acf78f3624abbd06d516e6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1db6103cb0f1d2bd6b19235d53ee7e98.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/666e172502a39172a8379934128101f8.png)
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3 . 已知函数
是
的导函数,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fc9ca8d13fcffa6e9fb07efdd05e4a56.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09f86f37ec8e15846bd731ab4fcdbacd.png)
A.“![]() ![]() |
B.“![]() ![]() |
C.若不等式![]() ![]() ![]() ![]() ![]() |
D.若![]() ![]() ![]() ![]() ![]() |
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4 . 函数
在区间
上单调递增,且在区间
上恰有两个极值点,则
的取值范围是______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/850add2235c90d798ab19c4371ebf268.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0ef023abc92ef73106fe81762d8ae87d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b8ec0ccdb6db6fbaeb1172e281ec22f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/074c228ffc7b1e306f8410afe7bc4b5c.png)
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解题方法
5 . 已知函数
,且
图象在
处的切线斜率为0.
(1)求
的值;
(2)令
,求
的最小值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7629ed91657427a9ab96120cfc9a6a4f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09f86f37ec8e15846bd731ab4fcdbacd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b384412acba251d87902ab928902f16.png)
(1)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
(2)令
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6c765461ae1a6c70f5cbdcb6c932a22b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4669810732b633b60dbeaf0bf57204f6.png)
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2024-05-31更新
|
776次组卷
|
3卷引用:福建省南平市2024届高三下学期第三次质量检测数学试题
名校
解题方法
6 . 在正四面体
中,
为棱
的中点,过点
的平面
与平面
平行,平面
平面
,平面
平面
,则
,
所成角的余弦值为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e7b7c83470489253394bd288d7c920df.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/670684ed4962fcebce7b5a140510d066.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c95f5f0202e1aa4febc79daad2aa7301.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/670684ed4962fcebce7b5a140510d066.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/94b785db474a35c54a20602e359571a2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
A.![]() | B.![]() | C.![]() | D.![]() |
您最近一年使用:0次
2024-05-31更新
|
664次组卷
|
2卷引用:福建省南平市2024届高三下学期第三次质量检测数学试题
解题方法
7 . 已知
,
,直线
,
相交于点
,且它们的斜率之积是4,记点
的轨迹为曲线![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
(1)求
的方程;
(2)不过
,
的直线
与
交于
,
两点,直线
与
交于点
,点
在直线
上,证明:直线
过定点.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/22d07a71ea5e77168d101526bd081433.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/12387f16bfc90abd7581d9f0f8d7a804.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7d0ff310aabd2282b539537ebed3f788.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/edc48974114e23f5a801843710c7ae21.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
(1)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
(2)不过
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a18722354086c42e62334983fc50eb6a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cd3b9e816b14051f785aa5aae72b8eed.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bbe61d39d080872caa8973a70a3b4955.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a439c8a01a6626d7a3f53af31ef0bcae.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf231f8f86fb922df4ca0c87f044cec3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf231f8f86fb922df4ca0c87f044cec3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b650820d7bed48ed67a2869ad8c65ff1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
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8 . 对任意非零实数
,当
充分小时,
.如:
,用这个方法计算
的近似值为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5dc51e97939a8966daa015535a801561.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/14e3ac443cac01e741f166e48cee9ae0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f09e442f77601cb12c592d2b930fd8a4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9317a6b2be7cdf9b7979f008750678e7.png)
A.1.906 | B.1.908 | C.1.917 | D.1.919 |
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解题方法
9 . 建盏为宋代名瓷之一,是中国古代黑瓷的巅峰之作,其采用福建建阳特有的高铁黏土和天然釉矿为原料烧制而成,工艺难度大,成功率低.假设建盏烧制开窑后经检验分为成品和废品两类,现有建盏10个,其中5个由工匠甲烧制,3个由工匠乙烧制,2个由工匠丙烧制,甲、乙、丙三人烧制建盏的成品率依次为0.2,0.1,0.3.
(1)从这10个建盏中任取1个,求取出的建盏是成品的概率;
(2)每件建盏成品的收入为1000元,每件废品的收入为0元.乙烧制的这3件建盏的总收入为
元,求
的分布列及数学期望.
(1)从这10个建盏中任取1个,求取出的建盏是成品的概率;
(2)每件建盏成品的收入为1000元,每件废品的收入为0元.乙烧制的这3件建盏的总收入为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f022950e0faa45b617d497b01b5292b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f022950e0faa45b617d497b01b5292b9.png)
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解题方法
10 . 如图,在四棱锥
中,
平面
,
,
,
.
,
分别为棱
,
上的动点(与端点不重合),且
.
平面
;
(2)若
,设平面
与平面
所成的角为
,求
的最大值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ccd4fd4b7a4d6b8ca0c5827c055a9ce7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b0fff774b4b0087a6f304ce930d359be.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ada414c44eda3553b2b8bd070511b965.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/da3b18adacdc2379dff16946537ea0ff.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e0629ce42392a7fe9be21d25c39c3e64.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9bff03bfdc11e703c0e8fd99133552fb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ca5dd496ee0c1170ef6dcc48266ee444.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf4c26f3f4d96117f087400a0f32ece8.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/44cdd1acd5353365eb41cfc2cabad999.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1885efcff0b903e314057dd153578600.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf4c26f3f4d96117f087400a0f32ece8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f3a282d19bf2c827a98d4443330f7ca1.png)
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