名校
解题方法
1 . 在长方形
中,
,点E在线段AB上,
,沿
将
折起,使得
,此时四棱锥
的体积为________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/de745f4a313e835454881b20c7fabeb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c1364213f546b37f8764ddcb59e36ae4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6e490f703eb6c9bb1278c78ebc2d661.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a25c28359f8d8da9eaf4672a6cf8ae4f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0c05986ad5fa244bc1aedf7b5d216544.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5164a3cc47e266446d49127e2ef10c37.png)
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名校
解题方法
2 . 设集合
,(
,
)且A中任意两数之和不能被5整除,则n的最大值为____________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c6bd3eec1b1e189c92c2db22ea773cd0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0704f453b2de48d36911f7db496bbf82.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dd4613271f782a90ab580131d09d03d1.png)
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3 . 如图,一块三角形铁片ABC,已知
,
,
,现在这块铁片中间发现一个小洞,记为点D,
,
.如果过点D作一条直线分别交AB,AC于点E,F,并沿直线EF裁掉
,则剩下的四边形EFCB面积的最大值为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3d2c15801fee2405573677484f5dcfa4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/33c99fc553ecb3e2afdb7058201bc642.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/26b566395b41fc587143d533f9756024.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f4aca5534bce25acaeb7379deed8f8f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/20d54e182a943f960a1885b8556d07a0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4c105d6ba18fbb0581fb982175e2eac9.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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解题方法
4 . 已知三棱锥
的所有棱长都是
分别是三棱锥
外接球和内切球上的点,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63397cda22cb1fad59cf966dfb588643.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be7ce62a6027d6d7051a6bb430dc7b09.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63397cda22cb1fad59cf966dfb588643.png)
A.三棱锥![]() ![]() |
B.三棱锥![]() ![]() |
C.![]() ![]() |
D.三棱锥![]() ![]() |
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2卷引用:湖南省郴州市第一中学等校2023-2024学年高一下学期5月联考数学试题
5 . 已知在直三棱柱
中,
,
为
的中点,在线段
上是否存在一点
,使得平面
平面
,若存在,请求出CN与
的比值;若不存在,说明理由;
(2)将两块形状与该直三棱柱完全相同的木料按如下图所示两种方案沿阴影面进行切割,把木料一分为二,留下体积较大的一块木料.根据你所学的知识,请判断采用哪一种方案会使留下的木料表面积较大,并说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2902d52b4fd9e2542207339b6d9d87b4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/56f7ba05c54b3de1f4378f7c8eb58328.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d88bf46ad08f9677c37eed1d0369329.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c1204a39f20cea0d6bfec8e72d07a62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3a70691e3884c6b35eace61575b12831.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6b4c0fdc09d58a130e5b9155cde03ce8.png)
(2)将两块形状与该直三棱柱完全相同的木料按如下图所示两种方案沿阴影面进行切割,把木料一分为二,留下体积较大的一块木料.根据你所学的知识,请判断采用哪一种方案会使留下的木料表面积较大,并说明理由.
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名校
解题方法
6 . 在复数域中,对于正整数
,满足
的所有复数
称为
次单位根,若一个
次单位根满足对任意小于
的正整数
,都有
,则称该
次单位根为
次本原单位根,规定1次本原单位根为1,例如当
时存在四个
次单位根
,因为
,
,因此只有两个
次本原单位根
,对于正整数
,设
次本原单位根为
,则称多项式
为
次本原多项式,记为
,规定
,例如
,请回答以下问题.
(1)直接写出
次单位根,并指出哪些是
次本原单位根(无需证明);
(2)求出
,并计算
,由此猜想
(无需证明);
(3)设所有
次本原单位根在复平面内对应的点为
,复平面内一点
所对应的复数
满足
,求
的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/65dc6548571fb407b11bd8e20fc9a860.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8c6e88d54d09eb7a4c8e934e296f8357.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/874631e1de2f86a9c0c8465db03fc7e2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fac3649308b528fd56545ba102dc42d5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b8860d9787671b53b1ab68b3d526f5ca.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5948aa4e0018b7e8e2d57f350ca5c718.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4291b447692fcd6becaeda53b10095c6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f6f79fedb9f7313e14fe9b7823011e5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b8860d9787671b53b1ab68b3d526f5ca.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2bd52d1543e19aea6fd5742a4328ddf5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/adc1b027c5aac5d97ee4eb33005fd9dd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09a213315196fb915fe48505cc9f65a6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e89220eb96a4757f2988362bc04e80c9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1ba63d9bf401b254e5857cab89cf27e2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/721b4bc405a8fe427893f4656e5918dd.png)
(1)直接写出
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cd3304e23f3b0f9569c4140ca89b6498.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cd3304e23f3b0f9569c4140ca89b6498.png)
(2)求出
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3ac0b017e80bfa576ff04b9a3a934927.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b962b1bcf29fcfc66941ca4fc14c5ea1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/719446337e4e8f52cf56bba204db24ed.png)
(3)设所有
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8c748e40ba21ac5063d3bccaa57ef278.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/588283c9af6716f9f56adec76399863a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e81e59019989b7dc2fb59b037ef6e010.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08b31f74f1bf8831816cede046b1bf50.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ee56eb9a6c76435dfec59163c289c9fe.png)
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|
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|
2卷引用:湖南省郴州市第一中学等校2023-2024学年高一下学期5月联考数学试题
名校
解题方法
7 . “阿基米德多面体”也称为半正多面体(semi-regularsolid),是由边数不全相同的正多边形为面围成的多面体,它体现了数学的对称美.如图所示,将正方体沿交于一顶点的三条棱的中点截去一个三棱锥,共可截去八个三棱锥,得到八个面为正三角形、六个面为正方形的一种半正多面体.已知
,则关于如图半正多面体的下列说法中,正确的有( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fcd0ced286a0fbc7e4862f8147264277.png)
A.该半正多面体的体积为![]() |
B.该半正多面体的顶点数![]() ![]() ![]() ![]() |
C.该半正多面体过![]() ![]() |
D.该半正多面体外接球的表面积为![]() |
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|
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3卷引用:湖南省耒阳市第一中学2023-2024学年高一下学期第三次月考数学试题
2024·全国·模拟预测
名校
解题方法
8 . 已知圆锥
的轴截面是顶角为
的等腰三角形,其母线长为
,底面圆周上有
,
两点,下列说法正确的有( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/18e5ef91fb27dd684a27ae7f1993cfba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c0211da37e92f915e781691296578ba0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
A.截面![]() ![]() |
B.若![]() ![]() ![]() ![]() |
C.若一只小蚂蚁从圆锥底面圆周上一点绕侧面一周回到原点,则最短路程为![]() |
D.当三棱锥![]() ![]() |
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9 . (1)对实系数的一元二次方程可以用求根公式求复数范围内的解,在复数范围解方程
;
(2)对一般的实系数一元三次方程
(
),由于总可以通过代换
消去其二次项,就可以变为方程
.在一些数学工具书中,我们可以找到方程
的求根公式,这一公式被称为卡尔丹公式,它是以16世纪意大利数学家卡尔丹(J. Cardan)的名字命名的.卡尔丹公式的获得过程如下:三次方程
可以变形为
,把未知数
写成两数之和
,再把等式
的右边展开,就得到
,即
.将上式与
相对照,得到
,把此方程组中的第一个方程两边同时作三次方,
,并把
与
看成未知数,解得
于是,方程
一个根可以写成
.
阅读以上材料,求解方程
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed344791b8b035ca04d4b5af7364cae5.png)
(2)对一般的实系数一元三次方程
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/48ad9d68d15b5d5121fcf99ebddaa986.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/20849c00c47cbdc43f18d53341b6c4e5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ae0f3c81f415857813838d4b9b714d56.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0ea05ab19c339e26f8268fbc7b6e918d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5dd275a6062b21f9c3e9155c7e0ba62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5dd275a6062b21f9c3e9155c7e0ba62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7ead1b77b69e6b51d6d483331fd01d41.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0bed1a02239821a616bc173181e7ed2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8c26aacdd3362aa65b2966045cbfcddf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f02c3aa1326c9b1e069b6997cd29bfa.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11792ad247341c0dbc80663dd0fa6f77.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7ead1b77b69e6b51d6d483331fd01d41.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d1e8aa11c220ffef18a553784e1ecc16.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/491db400b0e81be11e3fd8729fe61a41.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36accab23dbd172687769aea43e5781c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411a315870ed3e6d0e8ea885f1a04bcf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9a9930c09269f4f03794e38c17f6da67.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5dd275a6062b21f9c3e9155c7e0ba62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/49d63387694fd1caafce80adfb43c86b.png)
阅读以上材料,求解方程
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/93c3d494147195cf4f5e1fa3f6f5a0b9.png)
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10 . 在平行四边形
中,
,
,
,点
从
出发,沿
运动,则下列结论正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/305a88d4e0249bd16d48eda01331d2d4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/04ee826937d2add7a93aaa1422f8b736.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e075468e7fb0bf30229aec01a7205977.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6fd23cf0ee5cd9a31bd9923c03e2b159.png)
A.当点![]() ![]() ![]() |
B.当点![]() ![]() ![]() |
C.当点![]() ![]() ![]() |
D.![]() ![]() |
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2024-04-07更新
|
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2卷引用:湖南省衡阳县三校联考2023-2024学年高一下学期3月月考数学试题