1 . 已知椭圆
的左、右焦点分别为
,
,过点
的动直线l交E于A,B两点,且点A在x轴上方,直线
与E交于另一点C,直线
与E于另一点D.
(1)求
的面积最大值;
(2)证明:直线CD过定点.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7ff1455a4045eb93f482c0751840aea7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f5076289823db419f94e9c0c8f4aafd9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3fb78c5f885034612c0e030b920143d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f5076289823db419f94e9c0c8f4aafd9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e86dbcf83cd5d3421b3eed7be7dab32d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c3656055f5256cd06e636ea96e9f89c2.png)
(1)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e5eb2485f90dbfd0dfd6e7d179a856f5.png)
(2)证明:直线CD过定点.
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|
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|
3卷引用:云南省昆明市第一中学2024届高三第十次考前适应性训练数学试卷
解题方法
2 . 已知
是椭圆
上四个不同的点,且
是线段
的交点,且
,则直线
的斜率为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0c82a10b4f0c9323d726804c89dd9548.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4e0b4bbfa0ed04cd3c2454d99d64e29c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e584f799ea554fc5533925ead4672501.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5c4cd264c97c1f261229925cc5a6761.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e17736bcf530ea84bb4a1b10cb7ae94a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
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解题方法
3 . 南宋的数学家杨辉“善于把已知形状、大小的几何图形的求面积,体积的连续量问题转化为求离散变量的垛积问题”.在他的专著《详解九章算法·商功》中,杨辉将堆垛与相应立体图形作类比,推导出了三角垛、方垛、刍薨垛、刍童垛等的公式. 如图,“三角垛”的最上层有1个球,第二层有3个球,第三层有6个球……第
层球数比第
层球数多
,设各层球数构成一个数列
.
的通项公式;
(2)求
的最小值;
(3)若数列
满足
,对于
,证明:
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7a0876215b2fd463d151523cd3c6b447.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7a0876215b2fd463d151523cd3c6b447.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76aef4cdcb5af742ce28003b7b6c8c20.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76aef4cdcb5af742ce28003b7b6c8c20.png)
(2)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fba64e33de2e9b26c3ecd485a99df0bc.png)
(3)若数列
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f329b217e1051b23f0d61023cdc6e69.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/538f7dd59772ba33a6fbb271893b1720.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/930bc56406e69b785b37a83d48e36724.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3b947eaa62fc4796c9751afbd85f9681.png)
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解题方法
4 . 英国物理学家、数学家艾萨克·牛顿与德国哲学家、数学家戈特弗里德·莱布尼茨各自独立发明了微积分,其中牛顿在《流数法与无穷级数》
一书中,给出了高次代数方程的一种数值解法——牛顿法.如图,具体做法如下:一个函数的零点为
,先在
轴找初始点
,然后作
在点
处切线,切线与
轴交于点
,再作
在点
处切线,切线与
轴交于点
,再作
在点
处切线,以此类推,直到求得满足精度
的零点近似解
为止.
,初始点
,精度
,若按上述算法,求函数
的零点近似解满足精度时
的最小值(参考数据:
);
(2)设函数
,令
,且
,若函数
,
,证明:当
时,
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cd2638be8e76b7ce20f32accd865418d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11bc05f41215f9894e11d1df0465751a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/437339c289bb04793753bfb127f2c689.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0afb80007983e5b99dcdeebf87d18ff4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/423204bf2b2ea3f2f3149e50024b4f64.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/34632cf7058027def02525a8a0192b0b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0afb80007983e5b99dcdeebf87d18ff4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5604a6f0518feb8d6b3614a63c4d61de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/243989300efbd8c55ee767025490cac9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0afb80007983e5b99dcdeebf87d18ff4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3ac32cbe433e4360f46a12ebe57841ee.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f5a1dde83314d453181574bf00fa434d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/34732ae551c25032c24dacba0f7d1506.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6e93be15318d221ab55a6a7890eb3b0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bfa32997808121b79607346a4e46c26f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/214c2f418480c16be9481836e06643f3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d275fbb3ee5cd1177ca5a2ceecbbef0f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/16d03e6896c7f0e86c33e7b6b29b40d5.png)
(2)设函数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/62da56a08d6ba1f94a6167679a03cd34.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3176cd8ccd41d19af14fc053a9f7532a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e4ef6f920cf01e61596caa2243af1619.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fefae68a891e01bd5832c462b90a54e0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b942ae6d59bc0ba5b568a1bce5ef38cd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08115d6d9f876dea921a4d32260ff1fb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d96284d59f444eeb296135b54626c6a0.png)
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5 . 已知抛物线
,焦点为
,点
为曲线
的准线与对称轴的交点,过
的直线
与抛物线
交于
两点.
(1)证明:当
时,
与抛物线相切;
(2)当
时,求
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1bb4dd4670828f75bc573b52cdd02e1d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0ae6f48b9a53c0155a692509cf31f7e6.png)
(1)证明:当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9f9b9bb0f509e6f3d30858efb217c1f5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60d4a832771ba45d407f31000c8fcf37.png)
(2)当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a6901e8b018a80e917540462d2f3aadd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f4dfec890cdfdda355e19463f3be813.png)
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6 . 已知点
是双曲线
右支上两个不同的动点,
为坐标原点,则
的取值范围是_________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/80156fb43e5f33534186b96e657fd364.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8c7d6206b76c32474e7e3eb85aa55710.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/634ca185a6fd5b53d5d6f0db154d6d73.png)
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7 . 已知椭圆
:
的左右焦点分别为
,
,将曲线
上所有点的横坐标变为原来的
倍,纵坐标变为原来的
倍,得到曲线
,则下列说法正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1241216f3c1cb5e73043dd1037f556d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7fbb63a88cfee74765e99b2f8ae3874d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f5076289823db419f94e9c0c8f4aafd9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3fb78c5f885034612c0e030b920143d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1241216f3c1cb5e73043dd1037f556d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c94bb12cee76221e13f9ef955b0aab1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f3ffe7abc59e2f65d827c8eab8d36a.png)
A.曲线![]() |
B.曲线![]() ![]() |
C.曲线![]() ![]() ![]() ![]() |
D.若![]() ![]() ![]() ![]() |
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解题方法
8 . 已知函数
,且
在区间
上单调递增,则
的最小值为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/75d9579e38a3e7e2ca8d64db48ac91c8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09f86f37ec8e15846bd731ab4fcdbacd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d562dc22dfb3b81d0c3f88b54d063c2f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b0113fd4c7d157757571f9a009e02af.png)
A.0 | B.![]() | C.![]() | D.-1 |
您最近一年使用:0次
2024-06-12更新
|
456次组卷
|
3卷引用:云南省2024届高三“3+3+3”高考备考诊断性联考卷(三)数学试卷
名校
解题方法
9 . 材料一:英国数学家贝叶斯
在概率论研究方面成就显著,创立了贝叶斯统计理论,对于统计决策函数、统计推断等做出了重要贡献.贝叶斯公式就是他的重大发现,它用来描述两个条件概率之间的关系.该公式为:设
是一组两两互斥的事件,
,且
,
,则对任意的事件
,有
,
.
材料二:马尔科夫链是概率统计中的一个重要模型,也是机器学习和人工智能的基石,在强化学习、自然语言处理、金融领域、天气预测等方面都有着极其广泛的应用.其数学定义为:假设我们的序列状态是
,
,那么
时刻的状态的条件概率仅依赖前一状态
,即
.
请根据以上材料,回答下列问题.
(1)已知德国电车市场中,有
的车电池性能很好.
公司出口的电动汽车,在德国汽车市场中占比
,其中有
的汽车电池性能很好.现有一名顾客在德国购买一辆电动汽车,已知他购买的汽车不是
公司的,求该汽车电池性能很好的概率;(结果精确到0.001![](https://staticzujuan.xkw.com/quesimg/Upload/formula/04582116cd765fcc5a52f44279ad6c94.png)
(2)为迅速抢占市场,
公司计划进行电动汽车推广活动.活动规则如下:有11个排成一行的格子,编号从左至右为
,有一个小球在格子中运动,每次小球有
的概率向左移动一格;有
的概率向右移动一格,规定小球移动到编号为0或者10的格子时,小球不再移动,一轮游戏结束.若小球最终停在10号格子,则赢得6百欧元的购车代金券;若小球最终停留在0号格子,则客户获得一个纪念品.记
为以下事件发生的概率:小球开始位于第
个格子,且最终停留在第10个格子.一名顾客在一次游戏中,小球开始位于第5个格子,求他获得代金券的概率.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5e742ff4e5752d6e031f6430284ebf7e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/252bab154aa5bdc9b4bce4c0d43aaf73.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/98b495bde2a91e4a81db5a23b0691d2d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b16d0f702177ab62d9e520728fd18136.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b91f85fc4d2f3894351dd2c4d4f5c975.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df1f6165ced7d66fcfbf399fc660a5af.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/67de0630a8794aaf2015025f561fcce1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b91f85fc4d2f3894351dd2c4d4f5c975.png)
材料二:马尔科夫链是概率统计中的一个重要模型,也是机器学习和人工智能的基石,在强化学习、自然语言处理、金融领域、天气预测等方面都有着极其广泛的应用.其数学定义为:假设我们的序列状态是
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/daa5e9bd516f6282483b92cfe6074623.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8d42ce25b52b6c094880eca189edb205.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d4b49fdb5924134bfc54266f0fee35ec.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2eb150b73ea7c87972a0b57510a99472.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/efb7b7d1f7f2afc71dda3740f6cc6b9f.png)
请根据以上材料,回答下列问题.
(1)已知德国电车市场中,有
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b28555fa2f3a09261cb4e0305d390145.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/91edc7e2d4811f5ea6c01284cf00393a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63b971b2c43a814d35dfe0c1be4c45d9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/267c88e52743f3dedd4e60569cb958fe.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/91edc7e2d4811f5ea6c01284cf00393a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/04582116cd765fcc5a52f44279ad6c94.png)
(2)为迅速抢占市场,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/91edc7e2d4811f5ea6c01284cf00393a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3da684da6a14c603a81085cb37005564.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8b2a698891d42c70b597f0da4f215f09.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/56d266a04f3dc7483eddbc26c5e487db.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/59c709117ab1d3ef620883a732aed68b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c05b9832b09731a574d4a4adf7448de.png)
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2024-06-11更新
|
738次组卷
|
3卷引用:云南省2024届高三学期”3_3_3“高考备考诊断性联考卷(二)数学试题
10 . 用一个不垂直于圆锥的轴的平面截圆锥,当圆锥的轴与截面所成的角不同时,可以得到不同的截口曲线,也即圆锥曲线.探究发现:当圆锥轴截面的顶角为
时,若截面与轴所成的角为
,则截口曲线的离心率
.例如,当
时,
,由此知截口曲线是抛物线.如图,圆锥
中,
、
分别为
、
的中点,
、
为底面的两条直径,且
、
,
.现用平面
(不过圆锥顶点)截该圆锥,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f8dd0c52aca1675c17b9a019aa7901e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e44f6ec575a7e7efb670d5c39bdcc2e7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ffa3205b1df826d63914dcb55bb3ab43.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09dbcaa127022fbd6b6f13345196408a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/18e5ef91fb27dd684a27ae7f1993cfba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/defa5b53043ae802bb1af7d14374406d.png)
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A.若![]() |
B.若![]() ![]() ![]() |
C.若![]() |
D.若截口曲线是离心率为![]() ![]() |
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2024-06-08更新
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464次组卷
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2卷引用:云南省昆明市第三中学2024届高三下学期高考考前检测数学试卷