解题方法
1 . 将足够多的一批规格相同、质地均匀的长方体薄铁块叠放于水平桌面上,每个铁块总比其下层铁块向外伸出一定的长度,如下图,那么最上层的铁块最多可向桌缘外伸出多远而不掉下呢?这就是著名的“里拉斜塔”问题.将铁块从上往下依次标记为第1块、第2块、第3块、……、第n块,将前
块铁块视为整体,若这部分的重心在第
块的上方,且全部铁块整体的重心在桌面的上方,整批铁块就保持不倒.设这批铁块的长度均为1,若记第n块比第
块向桌缘外多伸出的部分的最大长度为
,则根据力学原理,可得
,且
为等差数列.
的通项公式;
(2)记数列
的前
项和为
.
①比较
与
的大小;
②对于无穷数列
,如果存在常数
,对任意的正数
,总存在正整数
,使得
,
,则称数列
收敛于
,也称数列
的极限为
,记为
;反之,则称
不收敛.请根据数列收敛的定义判断
是否收敛?并据此回答“里拉斜塔”问题.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8c5abd5f2fc2744d7f706656575b7262.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/12444d6e8d3b097a9d090e6ed06042e4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7a0876215b2fd463d151523cd3c6b447.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/96abfe2da27a63e6affb19a0c80236d9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ee45219629dd30af171588e646f8b12.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b7b78e4a03d4595f14be42054b61dfc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76aef4cdcb5af742ce28003b7b6c8c20.png)
(2)记数列
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76aef4cdcb5af742ce28003b7b6c8c20.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08eb71ecf8d733b6932f4680874dbbf3.png)
①比较
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08eb71ecf8d733b6932f4680874dbbf3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4c6b6c6934eda8f0838d0ba881be2211.png)
②对于无穷数列
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c1fd18a909cecbaee7115d6b15631d83.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/711c92626a97e6b778b3aa86e663ee97.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e4ccd4537f4dee2050ade38b972eb9b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/74d1d3b9d14068d68a7cff35ce3e872c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f4691ee07234d7cfc8a21bed1236c98.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c1fd18a909cecbaee7115d6b15631d83.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c1fd18a909cecbaee7115d6b15631d83.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1b85738365edd32d8df21b2d36518029.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c1fd18a909cecbaee7115d6b15631d83.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d013861990cf331c82eb453416ae31bc.png)
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名校
解题方法
2 . 在圆台
中,圆
的半径是2,母线
,圆
是
的外接圆,
,
,则三棱锥体积最大值为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e65ac334119ccd6204402a7aba29a55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f919bd3dde10dbbc076f7ec5149699.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2899e607479d8d1c47d954ae9ebb7144.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c4f6f74444b2b7947fc6e35c8d62322.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/84d81d732204a3c2384a27606f858677.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/68b40d0d2f3cdd8981bb792ad87efb42.png)
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3 . 若无穷数列
满足:对于
,其中
为常数,则称数列
为
数列.
(1)若一个公比为
的等比数列
为“
数列”,求
的值;
(2)若
是首项为1,公比为3的等比数列,在
与
之间依次插入数列
中的
项构成新数列
,求数列
中前30项的和
.
(3)若一个“
数列"
满足
,设数列
的前
项和为
.是否存在正整数
,使不等式
对一切
都成立?若存在,求出
的值;若不存在,说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83cf38189d5cbf627d2b82ac0eb76006.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/80d6f0757423edb2e5eed9bc8abf85af.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1010846eeec6c9da29640f5aa3f8738.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83cf38189d5cbf627d2b82ac0eb76006.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
(1)若一个公比为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9aa8a716a31b0f51b70fdf9bdb257909.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e976c0663fa749ca749f99842d21ca03.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9aa8a716a31b0f51b70fdf9bdb257909.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6399690401e29b0b652dec6448497708.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b4741eb4c177d75ca74fe2d36e52ecbc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e1cf52946ef832dd2fa7a82dcd6d1bcc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/362832fa3d3c13c1eafd565349d66dce.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0a532e15e232cb4b99a8d4d07c89575.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8f4b36b1b5f4d0aff4145e38842edaa6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/57ef6d44448092ebdb9e4a49d866a749.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d16765bfe96c4c2733afdf4099a33f5e.png)
(3)若一个“
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83cf38189d5cbf627d2b82ac0eb76006.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a8ae312d758938e1e030a93d78fa9d69.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/41cf1da18d91f7c98086553d157d1a87.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f1ae9a3b0b7aeb1545b65d91aa371b3c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aee956329e95a172d86c86b2f6af7aec.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9c0c6b2deb3a45dcb0c351566ae84f2f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e97769855336d73371930df1f187875e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aee956329e95a172d86c86b2f6af7aec.png)
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4 . 己知椭圆
的左、右顶点分别为
,右焦点为F.动直线l过F且与E相交于A,B两点,定点G使得
.
(2)直线m过点G且垂直于x轴,点P在m上,证明:若
三点共线,则
三点共线:
(3)椭圆E如图所示,请用“尺规作图”的方法在图中作出点F、点G,保留作图痕迹,并写出作图步骤.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8868e2ba4401d727f1bcb1f5483b48f5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/00442d96d695db2c58bf1fb7165fca94.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dd5f7f8631964382f4769c8fc020e6f7.png)
(2)直线m过点G且垂直于x轴,点P在m上,证明:若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2956ffa0de0f9d11afe72119b221264a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c7489e056192b00dc0973539cf36ab9c.png)
(3)椭圆E如图所示,请用“尺规作图”的方法在图中作出点F、点G,保留作图痕迹,并写出作图步骤.
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5 . 进位制是人们为了计数和运算方便而约定的记数系统,如果约定满二进一,就是二进制:满十进一,就是十进制:满十六进一,就是十六进制.k进制的基数就是k.我们日常生活中最熟悉、最常用的就是十进制.例如,数3721也可以表示为:
一般地,如果k是大于1的整数,那么以k为基数的k进制数可以表示为
.其中
.为了简便,也会把它写成一串数字连写在一起的形式:
,如果不加下标就默认是十进制.
(1)令集合
,将B中的元素按从大到小的顺序排列,则第100个数为多少?
(2)若
,记
为整数n的二进制表达式中0的个数,如
,求
的值.(用数字作答)
(3)十进制中的数999在其他进制中是否也可以表示成一个各位数字之和为27的三位数?如果能,请求出所有的k进制数;如果不能,请说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c8e187d488943587384ba81366d7cb2d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6bf78d6c2cd4fab5d71e969af0f530e5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1d47daf899fce1cb06151012a09153d9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/79224c6579e5f93906b81de9a7f8dbfd.png)
(1)令集合
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b963d591925c79c381bb8c7cf8121390.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/39bc26525689d068504cd9298b19d424.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7c51592137a3a852f5c802be493e065a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/39009f3279d0431b9b444634f18f355b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5a80cc2a98cd5e91efa4169a97d4e8e1.png)
(3)十进制中的数999在其他进制中是否也可以表示成一个各位数字之和为27的三位数?如果能,请求出所有的k进制数;如果不能,请说明理由.
您最近一年使用:0次
名校
6 . 已知函数
,且![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bda318adf65c6b6fd45f651365f52346.png)
(1)求
的最大值
(2)写出
与
的大小关系,并给出证明
(3)试问
能否作为
三边长?若能,给出证明,并探究
的外接圆的半径是否为定值?若不能,请说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1044dcf4fba551e1b7fbfeb895ea08c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bda318adf65c6b6fd45f651365f52346.png)
(1)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b692262286e03cc0536598789fab8699.png)
(2)写出
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/88fd5c1ef0fc722337a4984834829c84.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3e7bb46b41cd3f1f9b5621c20bf7fe07.png)
(3)试问
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b799aaa36edd0d10fc38925ce2e55045.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
您最近一年使用:0次
2024-06-12更新
|
154次组卷
|
2卷引用:福建省泉州市安溪第八中学2023-2024学年高一下学期6月份质量检测数学试题
名校
解题方法
7 . 如图,开车从
站到
站有3条路线.甲、乙、丙路线分别为![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4853b4705dee3de86e18a346ee3ae853.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8669a6aa7e782932422fe26986ff3dec.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/35ff324f42e4c0ebdc73afa6f3627a70.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9f4c4eb1dea2c12f31858ba9527c91.png)
.开车从
站到
站需要3分钟,从
站到
站需要2分钟,从
站到
站需要2分钟,从
站到
站需要,2.5分钟,从
站到
站需要
分钟,从
站到
站需要
分钟,从
站到
站需要
分钟,从
站到
站需要
分钟,受路上的红绿灯影响,
都是随机变量,且分布列如下
.
(1)若选择甲路线,开车从
站到
站的总时间为
分钟,求
的分布列;
(2)小张从这3条路线中选择1条,他在每站选择前进的方向时,都会等可能地选择其中一个方向,在他开车经过
站的前提下,若他开车从
站到
站的总时间少于5分钟的概率为0.4,求
的值;
(3)以各条路线开车需要的总时间的期望为依据,若三条路线中只有丙路线最快捷,求
的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4853b4705dee3de86e18a346ee3ae853.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8669a6aa7e782932422fe26986ff3dec.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/35ff324f42e4c0ebdc73afa6f3627a70.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9f4c4eb1dea2c12f31858ba9527c91.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/35deedd73b1aa36be696a3674b87c0bc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/895dc3dc3a6606ff487a4c4863e18509.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/895dc3dc3a6606ff487a4c4863e18509.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/87c7eb49a823f757461cd5260757b088.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5cd84a8f95166367063218ee03ffd5a7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/895dc3dc3a6606ff487a4c4863e18509.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8db31d2bbc9b044646fd026f239e7b62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0244fcb28c5a8fc66c4ba114162ee635.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/295fbfd4857081c1b7299a2247dae2f6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1a15534d805bcf37d4b8187def1cecd1.png)
2 | 2.5 | |
0.4 | 0.6 | |
1.5 | 2.5 | |
0.5 | 0.5 | |
2 | 3 | |
m | ||
2 | 3 | |
0.5 | 0.5 |
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f022950e0faa45b617d497b01b5292b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f022950e0faa45b617d497b01b5292b9.png)
(2)小张从这3条路线中选择1条,他在每站选择前进的方向时,都会等可能地选择其中一个方向,在他开车经过
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
(3)以各条路线开车需要的总时间的期望为依据,若三条路线中只有丙路线最快捷,求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
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2024-06-12更新
|
257次组卷
|
2卷引用:福建省“德化一中、永安一中、漳平一中”三校协作2023-2024学年高二下学期5月联考数学试题
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解题方法
8 . 球冠是指一个球面被平面所截得的曲面,截得的圆面是底,垂直于圆面的直径被截得的部分是高.如图,已知球的半径为20cm,球冠的高为10cm,现有3根长度相等的支柱
,
,
用于支撑球冠,立于水平的桌面上.若
,为使稳固支撑球冠,则应满足![](https://staticzujuan.xkw.com/quesimg/Upload/formula/38dd8aad9cfb5e1fe2a45d80923f1571.png)
___________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/602d0265aa2b89076b0cff90853f7cfa.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d7393358bb94b0df78fd4e29223257e1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81a3bcd3385a9fef291cfe6291d9e10c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4e6838e4c3fcca20d4381e91f1109b07.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/38dd8aad9cfb5e1fe2a45d80923f1571.png)
您最近一年使用:0次
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解题方法
9 . 在通用技术课上,老师给同学们提供了一个如图所示的木质四棱锥模型
,
为正三角形,
,
,
为线段
的中点.
平面
;
(2)过点
的平面
交
于点
,沿平面
将木质四棱锥模型切割成两部分,在实施过程中为了方便切割,请你完成以下两件事情:
①在木料表面应该怎样画线?(在答题卡的图上画线要保留辅助线,并写出作图步骤);
②在木质四棱锥模型中确定
点的位置,求
的值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/80c753cb1eb73fd8d136d00462970797.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ab2a2834d80ff574e79eae8ca8d4e94f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08ad8d16722f5b9e7fd2602f14d5ffbe.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5b0382c28547d3834ca71f3f0677695.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/68a83fdd2ba72a2dba0b6b10bb3e06b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0457394ce4f2dc8d940c565c94dcf557.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/500df0e782bb081e608f4bc1d576afcf.png)
(2)过点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6d94061dfdcef084c7594522ae9e512a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ccaee8f228ff24e7c89879bb5b999cf2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
①在木料表面应该怎样画线?(在答题卡的图上画线要保留辅助线,并写出作图步骤);
②在木质四棱锥模型中确定
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8136c029f4b31e25c56c70a1432cbe1a.png)
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解题方法
10 . 在某抽奖活动中,初始时的袋子中有3个除颜色外其余都相同的小球,颜色为2白1红.每次随机抽取一个小球后放回.抽奖规则如下:设定抽中红球为中奖,抽中白球为未中奖;若抽到白球,放回后把袋中的一个白色小球替换为红色;若抽到红球,放回后把三个球的颜色重新变为2白1红的初始状态.记第n次抽奖中奖的概率为
.
(1)求
,
;
(2)若存在实数a,b,c,对任意的不小于4的正整数n,都有
,试确定a,b,c的值,并证明上述递推公式;
(3)若累计中奖4次及以上可以获得一枚优胜者勋章,则从初始状态下连抽9次获得至少一枚勋章的概率为多少?
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bf83e20035c3afd6d26ebfd53d768a70.png)
(1)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b9cb8e6ff801523b0304576cd69fd2d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/797e67927616b141ed7c6b83f8b6f4fb.png)
(2)若存在实数a,b,c,对任意的不小于4的正整数n,都有
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9f7a0cdf4919f3a61788a57487780bfe.png)
(3)若累计中奖4次及以上可以获得一枚优胜者勋章,则从初始状态下连抽9次获得至少一枚勋章的概率为多少?
您最近一年使用:0次
2024-04-19更新
|
916次组卷
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4卷引用:福建省安溪铭选中学2023-2024学年高一下学期6月份质量检测数学试题