1 . 如图,在四棱锥
中,底面
是梯形,
,侧面
为正三角形,且与底面
垂直,E为
的中点,M在
上,满足
.
时,证明:
平面
;
(2)当二面角
为
时,求
的值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/642afba05807cdacf3ed4057d5dec3b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1e582d73b96ba649378379c3074d506d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/48f3c9abbd78e9a6840ee5f30381daac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/62634b76241cef6e250eee87dad489c7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/73b3cf0f585938ede9eca890a6eb326d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2f0b39562ebcbac4476e41725a66bb4c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1e582d73b96ba649378379c3074d506d.png)
(2)当二面角
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/06e8eea7f5526dba4c58723366b36c6e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15615de1a6df206dbd081251f676578e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df64046e91b047037f19e4032e3b6de3.png)
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解题方法
2 . 已知数列
满足
,
.
(1)求
,
,
,并求证:
;
(2)求数列
的前2n项和
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83cf38189d5cbf627d2b82ac0eb76006.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b065334d8f60c49f4bd3d9f1373fe4cd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c712dc627635bda129cf341fec2935bd.png)
(1)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3e88093a749c0d46e0ee931ecfaff925.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6c1ccc6c74b8754e9bcbb3f39a11b6f1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/daf464629fa321a6ff7401ab79f07083.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/465e0cb149bdd0170f8a6eaf66b4a90f.png)
(2)求数列
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83cf38189d5cbf627d2b82ac0eb76006.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3b9a0d7150fb24be3e28ef7f0e18be93.png)
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名校
3 . 某校开设了“五子棋”社团课,甲乙两位同学进行五子棋比赛,每局有一人先手(每局中先走第一颗棋),规则如下:每局输者下一局先手.已知甲先手时,甲赢的概率为
;乙先手时,乙赢的概率为
.假设每局无平局,且每局比赛的输赢相互独立,第一局甲先手.
(1)甲乙两位同学比赛两局,求甲至少赢1局的概率;
(2)记
为第
局比赛中甲赢的概率,求
,并计算连续比赛20局中,甲赢的概率大于
的局数.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8b2a698891d42c70b597f0da4f215f09.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eac97e6740365c85ad857aff85cefbe5.png)
(1)甲乙两位同学比赛两局,求甲至少赢1局的概率;
(2)记
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/59c709117ab1d3ef620883a732aed68b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c05b9832b09731a574d4a4adf7448de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/59c709117ab1d3ef620883a732aed68b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
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解题方法
4 . 某超市购进一批同种类水果,按照果径大小分为四类:不达标果、标准果、精品果、礼品果.质检技术人员从该批水果中随机选取100个,按果径大小分成5组进行统计:
(单位:
).统计后制成如下的频率分布直方图,并规定果径低于
为不达标果,在
到
之间为标准果,在
到
之间为精品果,达到
及以上的为礼品果.
,求
的分布列与数学期望;
(2)以频率估计概率,从这批水果中随机抽取
个,设其中恰有2个精品果的概率为
.当
最大时,求
的值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e63f596830b0572391b313e3c1b907d1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/21f3bf70722b22983c120d008d097602.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/29f9e4eac259f02179e45346f7fe2a1b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/29f9e4eac259f02179e45346f7fe2a1b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4db74a039efbf820b2e184f468633686.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4db74a039efbf820b2e184f468633686.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bbebf292ad30fa3b21a92b61eb68fd97.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bbebf292ad30fa3b21a92b61eb68fd97.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f022950e0faa45b617d497b01b5292b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f022950e0faa45b617d497b01b5292b9.png)
(2)以频率估计概率,从这批水果中随机抽取
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/50e3273deabbf8c7d700d340b71ca2eb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/019e032a954865d46eb35956a8fc2fe3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/019e032a954865d46eb35956a8fc2fe3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
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5 . 我市开展了“暖冬计划”活动,为高海拔地区学校加装供暖器.按供暖器的达标规定:学校供暖器的噪声不能超过50分贝、热效率不能低于
某地采购了一批符合达标要求的供暖器,经抽样检测,这批供暖器的噪声
单位:分贝
和热效率的频率分布直方图如图所示:
(1)求a,b的值;
(2)如果供暖器的噪声与热效率是独立的,从这批供暖器中随机抽2件,求恰有1件噪声不超过25分贝且热效率不低于
的概率;
(3)当
,设供暖器的噪声不超过
(分贝)的概率为
,供暖器的热效率不低于
的概率为
,求
的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/238e94eef445570873d15db2d04d1782.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fd995178601c2ad7b40f973d268c7bb7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/04582116cd765fcc5a52f44279ad6c94.png)
(1)求a,b的值;
(2)如果供暖器的噪声与热效率是独立的,从这批供暖器中随机抽2件,求恰有1件噪声不超过25分贝且热效率不低于
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/24c4bf61e073c899494b2fb3b767b108.png)
(3)当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/13620684da9724432d33a2489c63bedb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b30c7c297a88106f7380440c113f7a91.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8be646cd52d7f2f1714e7542e75810f2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5cf7b4e54130938f457d00a45977586e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/adad9633b73dfbbb3d84b4f15979e99e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cca4b2f545d6cfd6764ad19c7bc2c2f8.png)
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6 . 已知函数![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fc80f38b6d55c82cabe23189b34bd1c9.png)
(1)当
时,求
在点
处的切线方程;
(2)若
在区间
上单调递增,求实数a的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fc80f38b6d55c82cabe23189b34bd1c9.png)
(1)当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b550ee821ee1838384835e81fc34b67.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09f86f37ec8e15846bd731ab4fcdbacd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9c9f8845aa2b51c460f2d798c9f62fa3.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09f86f37ec8e15846bd731ab4fcdbacd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d562dc22dfb3b81d0c3f88b54d063c2f.png)
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7 . 已知函数
的最小正周期为![](https://staticzujuan.xkw.com/quesimg/Upload/formula/70f5389990c3a0c5373f3bd9fb2454c9.png)
(1)求函数
的单调递增区间;
(2)已知
的三边长分别为a,b,c,其所对应的角为A,B,C,且
,
,
,求该三角形的周长.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b4f7a080cc7738a3c11acbc19fecd9d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/70f5389990c3a0c5373f3bd9fb2454c9.png)
(1)求函数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09f86f37ec8e15846bd731ab4fcdbacd.png)
(2)已知
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/95f2d59590aa4817f957ccf6dc23f4d6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/468aa4abb9d9f7c3617068fc1cfd6f08.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1225fd03e8e8730dac8487dae5387635.png)
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解题方法
8 . 某娱乐节目闯关游戏共有三关,游戏规则如下:选手依次参加第一、二、三关,每关闯关成功可获得的奖金分别为200元、400元、600元,奖金可累加;若某关闯关成功,选手可以选择结束闯关游戏并获得相应奖金,也可以选择继续闯关;若有任何一关闯关失败,则连同前面所得奖金全部归零,闯关游戏结束.选手甲参加该闯关游戏,已知选手甲第一、二、三关闯关成功的概率分别为
,
,
,每一关闯关成功选择继续闯关的概率均为
,且每关闯关成功与否互不影响.
(1)求选手甲第一关闯关成功,但所得总奖金为零的概率;
(2)设选手甲所得总奖金为X,求X的分布列及其数学期望.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7294f5ae2a24ff42e84cd9773b2a7287.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bf31876698721a199c7c53c6b320aa86.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eac97e6740365c85ad857aff85cefbe5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
(1)求选手甲第一关闯关成功,但所得总奖金为零的概率;
(2)设选手甲所得总奖金为X,求X的分布列及其数学期望.
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2024-06-04更新
|
833次组卷
|
2卷引用:重庆市主城区2024届高三下学期学业质量调研抽测(第二次)数学试题
名校
9 . 如果存在实数对
使函数
,那么我们就称函数
为实数对
的“
型正余弦生成函数”,实数对
为函数
的“
型正余弦生成数对”.
(1)已知函数
的“4型正余弦生成数对”为
,求方程
在区间
上所有实根之和;
(2)若实数对
的“2型正余弦生成函数”
在
处取最大值,其中
,求
的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a64d924836b4292239d9726c6473d7f5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8b660b878e6c0f3590c50bf52f896acc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4fe7d5809da02c15a43a0e9a898b9086.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a64d924836b4292239d9726c6473d7f5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/595044a7750ab4f84519041979c3d780.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a64d924836b4292239d9726c6473d7f5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4fe7d5809da02c15a43a0e9a898b9086.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/595044a7750ab4f84519041979c3d780.png)
(1)已知函数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6a1cfb60420ff7e72c1b9d64f69ae063.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/425bdb703e21f599b68315be995b551b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/56c40363783d0e33e6a40e68957391ec.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/50e57682d2fe6f71ce86a38502e2f119.png)
(2)若实数对
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/46d552855e04ac50648a15e9b4aec868.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e915b67f8f747698b8b46d37bc453667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11abb76da45ffa52b47c3a6b9a03ac7e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/88fc13c376b1423dc2cefb3018bdc26e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1ee0a78ef89b08120fcf8b7cb0d013b1.png)
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10 . 如图所示的几何体是一个半圆柱和一个三棱锥的组合体.
是半圆柱的母线,
分别是底面直径BC和
的中点,
是半圆
上一动点,
是半圆
上的动点,
是圆柱的母线,延长
至
点使得
为
的中点,连接
,
构成三棱锥
.
;
(2)当三棱锥
的体积最大时,求平面
与平面
的夹角.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8ebf67d880172b27fefacc3c5b808eae.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a4d6cde991efd85f03f8801e745127a6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/56f7ba05c54b3de1f4378f7c8eb58328.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/683e17492ad37eeab880209057cb0feb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a18722354086c42e62334983fc50eb6a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f919bd3dde10dbbc076f7ec5149699.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2777840758e70e7dbbc18cef8f3d6d2b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4a696a182fff038a86b2bbe8ca099442.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7d0ff310aabd2282b539537ebed3f788.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/30513ea48bc1ef3ae78adac83d894f14.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d4d260c4df7b0dc180af6980d21f3371.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63397cda22cb1fad59cf966dfb588643.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf5ae8d145c5ce43e4cfc95fe6f563ed.png)
(2)当三棱锥
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63397cda22cb1fad59cf966dfb588643.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e367b683581c7cbe018078168f69efc5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6b36a70bc52a720ba8750aee4924307.png)
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